我有一个由“语句”列表组成的文件,每个语句都包含一个长度可变的逗号分隔的“列”列表,其中语句的结尾用分号表示:
head(
col1,
col2
);
head2(
col1,
col2,
col3
);
我有一个完整文件的工作语法,但是如果其中一列中有语法错误,那么错误消息的信息量就不是很大了,它基本上是说整个语句在开头的paren中很糟糕。在
所以我想单独分析每一列,这样就可以更详细地报告该列中的错误。下面将解析整个文件(两个语句),并从parse actions打印每个语句和列列表:
^{pr2}$导致:
abc(d 45, e, f g h); s2("much" "stuff", 34 48);
++ ['abc'] ++ 0 ++
== ['d 45, e, f g h'] === 4 ==
++ ['s2'] ++ 21 ++
== ['"much" "stuff", 34 48'] === 24 ==
[['abc', 'd 45, e, f g h'], ['s2', '"much" "stuff", 34 48']]
但当我试图通过取消注释cols = commaSeparatedList(toks)
来解析列列表时,一切都会爆炸:
abc(d 45, e, f g h); s2("much" "stuff", 34 48);
++ ['abc'] ++ 0 ++
Traceback (most recent call last):
File "pt.py", line 27, in <module>
print(script.parseString(ss))
File "pyparsing.py", line 1115, in parseString
loc, tokens = self._parse( instring, 0 )
File "pyparsing.py", line 989, in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File "pyparsing.py", line 2732, in parseImpl
loc, tokens = self.expr._parse( instring, loc, doActions, callPreParse=False )
File "pyparsing.py", line 989, in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File "pyparsing.py", line 2624, in parseImpl
return self.expr._parse( instring, loc, doActions, callPreParse=False )
File "pyparsing.py", line 989, in _parseNoCache
loc,tokens = self.parseImpl( instring, preloc, doActions )
File "pyparsing.py", line 2378, in parseImpl
loc, exprtokens = e._parse( instring, loc, doActions )
File "pyparsing.py", line 1015, in _parseNoCache
tokens = fn( instring, tokensStart, retTokens )
File "pyparsing.py", line 779, in wrapper
ret = func(*args[limit[0]:])
TypeError: parse_col() missing 3 required positional arguments: 'strng', 'loc', and 'toks'
我的问题不涉及多线程或递归,但它似乎确实表明pyparsing的可重入调用有问题,可能与context in pyparsing parse actions besides globals有关。在
有没有一种简单的方法可以从一个动作调用pyparsing例程,一个比这个问题的答案更简单的方法?在
改变
到
^{pr2}$几乎可以修复它,至少在您给出的数据示例中是这样。然而,“much”“stuff”似乎破坏了csl解析器,可能是因为它希望在“much”的结尾后面有一个逗号。在
相关问题 更多 >
编程相关推荐