擅长:python、mysql、java
<p>对于Python2.6<</p>
<pre><code>import itertools
data_array = [[0, 0, 1], [1, 1, 1], [1, 1, 1], [1, 0, 1]]
dict_ = {}
for list_, count in itertools.groupby(data_array):
dict_.update({tuple(list_), len(list(count))})
</code></pre>