pygame的“菜单类”示例可以单独使用，但在引入外部代码时则不行

Question

试图利用pygame的Menu类将菜单引入到我的游戏中，即使它本身运行得非常好，当我将它添加到我的项目中时，甚至没有调用示例代码之外的任何函数，它给了我一个错误：“AttributeError:'Event'object has no attribute'key'”我的头撞了好一阵子，所以如果有人能帮我一把，我将不胜感激。另外，缩进可能会因为我粘贴到这个代码框中而倾斜。请假设在实际游戏代码中，间距是适当的。在

示例代码：

def main():
   # Initialize Pygame
   pygame.init()

   # Create a window of 800x600 pixels
   screen = pygame.display.set_mode((width, height))

   # Set the window caption
   pygame.display.set_caption("Space Exploder")

   # Create 3 diffrent menus.  One of them is only text, another one is only
   # images, and a third is -gasp- a mix of images and text buttons!  To
   # understand the input factors, see the menu file
   menu = cMenu(50, 50, 20, 5, 'vertical', 100, screen,
               [('Start Game', 1, None),
                ('Load Game',  2, None),
                ('Options',    3, None),
                ('Exit',       4, None)])

   # Center the menu on the draw_surface (the entire screen here)
   menu.set_center(True, True)

   # Center the menu on the draw_surface (the entire screen here)
   menu.set_alignment('center', 'center')

   # Create the state variables (make them different so that the user event is
   # triggered at the start of the "while 1" loop so that the initial display
   # does not wait for user input)
   state = 0
   prev_state = 1

   # rect_list is the list of pygame.Rect's that will tell pygame where to
   # update the screen (there is no point in updating the entire screen if only
   # a small portion of it changed!)
   rect_list = []

   # Ignore mouse motion (greatly reduces resources when not needed)
   pygame.event.set_blocked(pygame.MOUSEMOTION)

   # The main while loop
   while 1:
      # Check if the state has changed, if it has, then post a user event to
      # the queue to force the menu to be shown at least once
      if prev_state != state:
         pygame.event.post(pygame.event.Event(EVENT_CHANGE_STATE, key = 0))
         prev_state = state

      # Get the next event
      e = pygame.event.wait()


      # Update the menu, based on which "state" we are in - When using the menu
      # in a more complex program, definitely make the states global variables
     # so that you can refer to them by a name



     if e.type == pygame.KEYDOWN or e.type == EVENT_CHANGE_STATE: 
         if state == 0:
            ## ERROR BELOW THIS LINE ERROR BELOW THIS LINE ERROR BELOW THIS LINE
              rect_list, state = menu.update(e, state) ### ERROR HERE  <----------- 
         elif state == 1:
            print 'Start Game!'
            state = 0

         elif state == 2:
            print 'Load Game!'
            state = 0
         elif state == 3:
            print 'Options!'
            state = 0
         else:
            print 'Exit!'
            pygame.quit()
            sys.exit()

      # Quit if the user presses the exit button
      if e.type == pygame.QUIT:
         pygame.quit()
         sys.exit()

      # Update the screen
      pygame.display.update(rect_list)


## ---[ The python script starts here! ]----------------------------------------
# Run the script
if __name__ == "__main__":
   main()

我的代码只是在示例代码之前呈现。没有对示例代码进行任何更改，但是简单地将我的代码放在那里会导致“AttributeError:'Event'object has No attribute'key'”错误。我在示例代码中标记了与代码耦合时发生错误的位置。在

^{pr2}$