擅长:python、mysql、java
<p>尝试:</p>
<pre><code>if "VALUE1" in entry:
foo()
</code></pre>
<p>确定<code>"VALUE1"</code>字符串是否在<code>entry</code>dict的键集中</p>
<p>你的逻辑大概是这样的:</p>
<pre><code>if "VALUE1" not in entry or "VALUE2" not in entry:
print "Values not found"
</code></pre>
<p>此测试完全不需要<code>try</code>块。</p>