Python字典，相当于pymongo语句

Question

我有一本像Python一样的字典

{'OR': [{'AND': [{'column': 'XXX', 'operator': '=', 'value': u'M'}, {'column': 'XXX', 'operator': '=', 'value': 'N'}]}, {'column': 'YYY', 'operator': '>=', 'value': '3.0'}]}

现在，我想把它转换成

^{pr2}$

这显然是我认为的相当于pymongo的说法。在

到目前为止，我写的代码是这样的：

FILTMAP = {'>=': '$gte', '<=': '$lte', '>': '$gt', '<': '$lt', "!=":"$ne"}
CONJUNCTION_MAP = {"AND":"$and", "OR":"$or"}

def gen_mongo_filters_json(filter, supplied_key="")
    first_key = filters.keys()[0]
    if first_key == 'OR' or first_key == 'AND':

        if supplied_key == "":      

            return_dict[CONJUNCTION_MAP[first_key]] = []
        else:            
            temp_dict[CONJUNCTION_MAP[first_key]] = []
            #return_dict[supplied_key] = temp_dict
        for i in range (len(filters[first_key])):
            if supplied_key == "":               
                return_dict[CONJUNCTION_MAP[first_key]].append(gen_mongo_filters_json(filters[first_key][i], first_key))
            else:
                temp_dict[CONJUNCTION_MAP[first_key]].append(gen_mongo_filters_json(filters[first_key][i], first_key))
                return_dict[CONJUNCTION_MAP[supplied_key]].append(temp_dict)
    else:
        operator = filters['operator']
        if operator == "=":
            ret_dict = {filters['column']:filters['value']
            return ret_dict
        else:
            operator = FILTMAP[operator]
            ret_dict = {filters['column']:{operator:filters['value']}}
            return ret_dict
    return return_dict

它产生的输出是：

 {u'$or': [{u'$and': [{u'Engine': u'MSN'}, {u'Engine': u'Google'}]}, {u'$and': [{u'Engine': u'MSN'}, {u'Engine': u'Google'}]}, {...}, {u'Imps': {u'$gte': 3.0}}]}

它接近于解，但不是精确解。它适用于像

{'AND': [{'column': 'XXX', 'operator': '=', 'value': 'M'}, {'column': 'XXX', 'operator': '=', 'value': 'N'}]}

OR

{'column': 'YYY', 'operator': '>', 'value': '1000'}

你能给我指个方向吗？在

（我们的想法是创建一个通用的。所以，我想在pymongo语句中生成与任何有效python字典等价的语句。最小值是最后一个）

Answer 1

示例代码不运行，但假定

{'OR': [{'AND': [{'column': 'XXX', 'operator': '=', 'value': 'M'}, {'column': 'YYY', 'operator': '=', 'value': 'N'}]}, {'column': 'YYY', 'operator': '>=', 'value': '3.0'}]}

应转换为

^{pr2}$

使用这样的方法：

FILTMAP = {'>=': '$gte', '<=': '$lte', '>': '$gt', '<': '$lt', "!=":"$ne"}
CONJUNCTION_MAP = {"AND":"$and", "OR":"$or"}

def convert_column(dic):
    if not dic['operator'] in FILTMAP:
        return {dic['column']: dic['value']}
    else:
        value = float(dic['value']) if dic['operator'] == "!=" else dic['value']
        return {dic['column']: {FILTMAP[dic['operator']]: value}}

def convert(dic):
    for k,v in dic.items():
        if isinstance(v, list):
            if k in CONJUNCTION_MAP:
                k = CONJUNCTION_MAP[k]
            return {k: [convert(i) for i in v]}
        else:
            return convert_column(dic)

我不知道将'3.0'转换为3.0是否重要。线

value = float(dic['value']) if dic['operator'] == "!=" else dic['value']

是相当老套的，你想用一些适当的逻辑来代替它来处理这些情况。在

Answer 2

谢谢你的回答。我也发现了一些事情。这是完整的代码

FILTMAP = {'>=': '$gte', '<=': '$lte', '>': '$gt', '<': '$lt', "!=":"$ne"}
CONJUNCTION_MAP = {"AND":"$and", "OR":"$or"}


def gen_mongo_filters_json(filters, supplied_key=""):
    return_dict = {}
    temp_dict = {}
    first_key = filters.keys()[0]
    if first_key == 'OR' or first_key == 'AND':

        if supplied_key == "":

            return_dict[CONJUNCTION_MAP[first_key]] = []
        else:            
            temp_dict[CONJUNCTION_MAP[first_key]] = []
            #return_dict[supplied_key] = temp_dict"""
        for i in range (len(filters[first_key])):
            if supplied_key == "":
                return_dict[CONJUNCTION_MAP[first_key]].append(gen_mongo_filters_json(filters[first_key][i], first_key))
            else:
                for i in range (len(filters[first_key])):
                    temp_dict[CONJUNCTION_MAP[first_key]].append(gen_mongo_filters_json(filters[first_key][i], first_key))
                return temp_dict
    else:
        operator = filters['operator']
        if operator == "=":
            ret_dict = {filters['column']:filters['value']}
            return ret_dict
        else:
            operator = FILTMAP[operator]
            ret_dict = {filters['column']:{operator:filters['value']}}
            return ret_dict
    return return_dict


if __name__ == "__main__":

    print gen_mongo_filters_json({'OR': [{'AND': [{'column': 'XXX', 'operator': '=', 'value': 'M'}, {'column': 'XXX', 'operator': '=', 'value': 'N'}]}, {'AND': [{'column': 'PPP', 'operator': '=', 'value': 'R'}, {'column': 'DDD', 'operator': '=', 'value': 'T'}]}]})
enter code here

请让我知道你的评论

我试过了

^{pr2}$

这是输出

{u'YYY': {u'$gt': u'1000'}}

{u'$and': [{u'XXX': u'M'}, {u'XXX': u'N'}]}

{u'$or': [{u'$and': [{u'XXX': u'M'}, {u'XXX': u'N'}]}, {u'YYY': {u'$gte': u'3.0'}}]}

{u'$or': [{u'$and': [{u'XXX': u'M'}, {u'XXX': u'N'}]}, {u'$and': [{u'PPP': u'R'}, {u'DDD': u'T'}]}]}

谢谢你的回答。也不错。我现在就试试。在

还有一件事，我实际上在我的示例代码中忽略了“值”的考虑。我很感谢你指出这一点。我已经有办法做到了。不管怎样，谢谢你。在