三角图程序

Question

我正在尝试用python编写一个程序，它应该从示例.txt发生3次以上。忽略单词和特殊字符的大小写，输出应按频率排序。在

我的老师告诉我，我只需要改两行字！但是我把Python弄瞎了。对我来说，代码看起来是正确的，但它确实有效。在

with open("examen.txt") as f:
    data = f.read()
    text = data.replace("\xad", "")

words = []
for word in data.lower().split():
    word = word.strip("‚‘!,.:«»-()'_#-–„“*?")
    if word != "":
        if not word[-1].isalnum():
            print(repr(word))
        words.append(word)

trigrams = {}
for i in range(len(words)):
    word = words[i]
    nextword = words[i + 1]
    nextnextword = words[i + 2]
    key = (word, nextword, nextnextword)
    trigrams[key] = trigrams.get(key, 0) + 1

l = list(trigrams.items())
l.sort(key=lambda x: (x[1], x[0]))
l.reverse()
for key, count in trigrams:
    if count < 3:
        break
    word = key[0]
    nextword = key[1]
    nextnextword = key[2]
    print(word, nextword, nextnextword, count)

Answer 1

当您构建三元组时，您遍历到words太深，而在最后一个循环中没有打印出正确的数据结构。在

换两行我会写-

with open("examen.txt") as f:
    data = f.read()
    text = data.replace("\xad", "")

words = []
for word in data.lower().split():
    word = word.strip("‚‘!,.:«»-()'_#-–„“*?")
    if word != "":
        if not word[-1].isalnum():
            print(repr(word))
        words.append(word)

trigrams = {}
for i in range(len(words) - 2):
    word = words[i]
    nextword = words[i + 1]
    nextnextword = words[i + 2]
    key = (word, nextword, nextnextword)
    trigrams[key] = trigrams.get(key, 0) + 1

l = list(trigrams.items())
l.sort(key=lambda x: (x[1], x[0]))
l.reverse()
for key, count in l:
    if count < 3:
        continue
    word = key[0]
    nextword = key[1]
    nextnextword = key[2]
    print(word, nextword, nextnextword, count)