擅长:python、mysql、java
<pre><code> i=0
for c in courts:
court_id = names[i]
i=i+1
weekday_key = db.Key.from_path('Courts', c.key().name(), 'Days', weekday)
reservation=Reservations.all()
reservation.ancestor(weekday_key)
nlimit=2*len(times)
reservations = reservation.fetch(limit=nlimit)
</code></pre>
<p>我不喜欢这个答案的地方是<code>weekday_key</code>在法庭上对所有c都是一样的。这似乎不对。在</p>