我正在寻找比较两个字符串并能够返回的方法,作为单独的字符串:
示例:
A = "123 ABC"
B = "135 AZ"
thingamajigger(A, B) # would give all these:
intersect = "13 A" # (includes space)
exclusion = "2BCZ5"
a_minus_b = "2BC"
b_minus_a = "5Z"
a_minus_b
很简单。。。但如果有一种奇特的单列方式来实现它,那么我是开放的。
for i in B:
A = A.replace(i, "")
这有点像对字符串的布尔操作。
使用^{} :
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