我试图让用户浏览目录位置的文件,以获取excel数据。 到目前为止,broswe功能可以工作并显示为一个标签,但是尝试将标签返回到任何按钮选项的函数中,比如texas(),是行不通的。 我从shell得到的以下错误是:
"unsupported operand type(s) for +: 'instance' and 'str'"
那么如何将标签值转换为字符串并使其工作?在
代码:
from Tkinter import *
import tkFileDialog
import sys
if sys.version_info[0] < 3:
import Tkinter as Tk
else:
import tkinter as Tk
import os
import tkMessageBox
root = Tk.Tk()
root.title("Excel Map Conversion")
root.geometry("450x400")# width x height
def browse_gainInfo():
currentDir = os.getcwd()
fname = tkFileDialog.askdirectory(parent=root, initialdir=currentDir, title="Please Select the Folder for Map Data Input")
pathlabel.config(text=fname)
filepath = StringVar()
def texas():
os.startfile(browseLink + '/Texas/Texas_conversion.py')
def state():
os.startfile(filepath.get() + '\State\StateConv.py')
def college():
os.startfile(filepath.get() + '\College\CollegeConv.py')
def underGrad():
os.startfile(filepath.get() + '\Undergraduate\undergrad_conversion.py')
def grad():
os.startfile(filepath.get()+ '\Graduate\graduate_conversion.py')
browseLabel = Label(root, text="Browse for source of Map Data").pack()
browse1 = Tk.Button(root, text='Browse', width =6, command = browse_gainInfo)
browse1.pack()
pathlabel= Label(root)
pathlabel.pack()
browseLink = StringVar(pathlabel)
label = Label(root, text="\nEnter in the filepath for the map files: \n").pack()
link = Entry(root, textvariable = filepath).pack()
label2 = Label(root, text ="\n\tPlease select from the following options:\n").pack()
button1 = Button(root, text = "College", command = college).pack()
button2 = Button(root, text= "State", command = state).pack()
button3 = Button(root, text="Texas", command = texas).pack()
button4 = Button(root, text ="Undergraduate", command = underGrad).pack()
button5 = Button(root, text ="Graduate", command = grad).pack()
#kick off the event loop
root.mainloop()
来自tkinterbook:
这可能对你所做的没有必要。我也不是你想做的那样。。。但似乎您试图以迂回的方式创建
textvariable
。在相关问题 更多 >
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