sikuli python脚本上的.sendto（）方法在windows上不起作用

Question

我在windows上开发了一个使用以下代码的sikuli python脚本：

from socket import AF_INET, SOCK_DGRAM
import sys
import socket
import struct, time

host = "pool.ntp.org"
port = 123
buf = 1024
address = (host,port)
msg = '\x1b' + 47 * '\0'

# reference time (in seconds since 1900-01-01 00:00:00)
TIME1970 = 2208988800L # 1970-01-01 00:00:00

# connect to server
client = socket.socket( AF_INET, SOCK_DGRAM)
client.sendto(msg, address)
msg, address = client.recvfrom( buf )

t = struct.unpack( "!12I", msg )[10]
t -= TIME1970

current_time = time.ctime(t).replace(" "," ")

这段代码在linux下或windows上的python脚本中运行良好，但是如果我在windows上的sikulix上使用此代码，它会崩溃（在第行=>；客户端.sendto（msg，address））出现以下错误：

^{pr2}$

你知道为什么和怎么修理吗？在

Answer 1

在这个讨论Sikuli如何与Jython进行互操作的线程中，您的问题得到了讨论并得到了明显的解决（这看起来像是一个Jython bug）：https://bugs.launchpad.net/sikuli/+bug/1464105

我检查了解决方案；这段代码在sikulixide中适用于windows10。基本上在顶部添加了初始化头：

import sys, _socket
from socket import AF_INET, SOCK_DGRAM
if _socket.NIO_GROUP.isShutdown():
    print "RE-CREATING NIO_GROUP"
    _socket.NIO_GROUP = _socket.NioEventLoopGroup(2, _socket.DaemonThreadFactory("PyScan-Netty-Client-%s"))
    sys.registerCloser(_socket._shutdown_threadpool)
import socket
import struct, time

host = "pool.ntp.org"
port = 123
buf = 1024
address = (host,port)
msg = '\x1b' + 47 * '\0'

# reference time (in seconds since 1900-01-01 00:00:00)
TIME1970 = 2208988800L # 1970-01-01 00:00:00
print "Before socket operation"
# connect to server
client = socket.socket( AF_INET, SOCK_DGRAM)
client.sendto(msg, address)
print "After socket operation"
msg, address = client.recvfrom( buf )
t = struct.unpack( "!12I", msg )[10]
t -= TIME1970

current_time = time.ctime(t).replace(" "," ")
print current_time