下面的代码是pythonquickbase模块的一部分,已经有很长时间没有更新了。下面显示的函数之一的帮助文本不清楚如何传递参数来上载文件(文件的值实际上是base64编码的)。在
def add_record(self, fields, named=False, database=None, ignore_error=True, uploads=None):
"""Add new record. "fields" is a dict of name:value pairs
(if named is True) or fid:value pairs (if named is False). Return the new records RID
"""
request = {}
if ignore_error:
request['ignoreError'] = '1'
attr = 'name' if named else 'fid'
request['field'] = []
for field, value in fields.iteritems():
request_field = ({attr: to_xml_name(field) if named else field}, value)
request['field'].append(request_field)
if uploads:
for upload in uploads:
request_field = (
{attr: (to_xml_name(upload['field']) if named else upload['field']),
'filename': upload['filename']}, upload['value'])
request['field'].append(request_field)
response = self.request('AddRecord', database or self.database, request, required=['rid'])
return int(response['rid'])
有人能帮助我如何传递参数来添加记录吗。在
根据您提供的定义,您似乎需要传递一个字典数组,每个字典都提供
uploads
参数的字段名/id、文件名和文件的base64编码。因此,如果我有一个表,其中我将颜色的名称记录到名为“color”的字段,字段id为19,将示例图像记录到字段id为21的“sample image”字段中,我相信我的方法调用如下所示:或者,如果使用字段名:
^{pr2}$client
只是您先前使用此模块拥有的任何构造函数实例化的对象。在相关问题 更多 >
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