擅长:python、mysql、java
<p>只需将它们作为<code>list</code>/<code>tuple</code>添加到原始列表中:</p>
<pre><code>items = []
for i in response['Contents']: # assuming response['Contents'] is a list
items.append([
's3://' + response['Name'] + '/' + i['Key'],
i['Key'].rsplit('/', 1)[-1],
i['Size']
])
</code></pre>