Python中的while循环错误

Question

如果您能帮助调试此代码，我将不胜感激：

testing = """There is something unique about this line
in that it can span across several lines, which is unique and
useful in python."""

listofthings = []

i = 0
while i < len(testing):
    if testing[i] == " ":
        listofthings.append(i + 1)

    i = i + 1

listofthings.insert(0, 0)
listofthings.append(len(testing))

print listofthings

word_list = []

i = 0

while i < len(listofthings):
    l = i + 1
    x = listofthings[i]
    y = listofthings[l]

    word = testing[x:y]
    word_list.append(word)

    i = l

print word_list 

我不知道为什么会出现index out of range错误。我明白错误的含义，但不确定我做错了什么。奇怪的是，只有当我运行上面的代码时才会发生这种情况。运行此程序时不会出现任何错误：

^{pr2}$

我对Python相当陌生（将持续三天），所以我确信这是一个被忽略的愚蠢语法错误。。。在

Answer 1

while i < len(listofshit):
    l = i + 1
    x = listofshit[i]
    y = listofshit[l]

当i对应于最后一个元素时

^{pr2}$

您正试图访问最后一个元素旁边的元素。这就是它抛出错误的原因。在

Answer 2

l = i + 1
x = listofshit[i]
y = listofshit[l]

word = testing[x:y]
word_list.append(word)

当i=length-1时，则y=length，这是一个错误。Python数组索引从0开始，因此最大地址是length-1

Answer 3

列表listofshit的长度为21，索引范围从0到20。在最后一个循环中，i是20，l是21，所以有一个超出范围的错误。我想下面的代码就是你想要的：

testing = """There is something unique about this line
in that it can span across several lines, which is unique and
useful in python."""

listofshit = []

i = 0
while i < len(testing):
    if testing[i] == " ":
        listofshit.append(i)

    i = i + 1

listofshit.insert(0, 0)
listofshit.append(len(testing))


word_list = []
i = 0

while i < len(listofshit) - 1:
    l = i + 1
    x = listofshit[i]
    y = listofshit[l]
    word = testing[x:y]
    word_list.append(word)

    i = l

print word_list