Spotipy:如何将auth令牌传递给clien

2024-04-19 06:27:21 发布

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我正在尝试使用spotipy python库构建一个应用程序来访问spotifyapi。在

我的oauth代码如下所示,除了使用正确的auth参数初始化客户机之外,它似乎可以正常工作。在

self.sp_auth=spotipy.oauth2.SpotifyOAuth(secrets.sp_auth_id,
                                secrets.sp_auth_pw, secrets.sp_callback_url,
                                scope="playlist-modify-public user-library-read", state=state)

。。。在

^{pr2}$

向用户发送url。 用户表示已给予权限后: 身份验证码从Web服务器获取并用于生成令牌。在

self.auth_token=self.sp_auth.get_access_token(self.auth_code)

在self.auth_令牌然后看起来像这样:

{'access_token'  : 'BQD ... qE7K3PBZKB6iZFU3_4p', 
 'token_type'    : 'Bearer',
 'expires_in'    : 3600,
 'refresh_token' : 'AQCOS2Xo ... MK09ry7-a-fl61OwhuO1Q',
 'scope'         : 'playlist-modify-public user-library-read',
 'expires_at'    : 1548247835}

然后我像这样初始化spotipy客户机模块:

self.sp = spotipy.Spotify(auth=self.auth_token)

然后我尝试以下方法:

playlists = self.sp.current_user_playlists(limit=10)

这引发了这个例外:

Traceback (most recent call last):
File "/usr/local/lib/python3.6/dist-packages/spotipy/client.py", line 119, in _internal_call
    r.raise_for_status()
  File "/usr/local/lib/python3.6/dist-packages/requests/models.py", line 940, in raise_for_status
    raise HTTPError(http_error_msg, response=self)
requests.exceptions.HTTPError: 400 Client Error: Bad Request for url: https://api.spotify.com/v1/me/playlists?limit=10&offset=0

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/usr/local/lib/python3.6/dist-packages/telegram/ext/dispatcher.py", line 279, in process_update
    handler.handle_update(update, self)
  File "/usr/local/lib/python3.6/dist-packages/telegram/ext/callbackqueryhandler.py", line 143, in handle_update
    return self.callback(dispatcher.bot, update, **optional_args)
  File "spotify_playlist_bot_v2.py", line 140, in button_auth_done
    User.data[user_id].msg_start(bot, update)
  File "spotify_playlist_bot_v2.py", line 84, in msg_start
    self.msg_choose_playlist()
  File "spotify_playlist_bot_v2.py", line 90, in msg_choose_playlist
    playlists = self.sp.current_user_playlists(limit=10)
  File "/usr/local/lib/python3.6/dist-packages/spotipy/client.py", line 355, in current_user_playlists
    return self._get("me/playlists", limit=limit, offset=offset)
  File "/usr/local/lib/python3.6/dist-packages/spotipy/client.py", line 146, in _get
    return self._internal_call('GET', url, payload, kwargs)
  File "/usr/local/lib/python3.6/dist-packages/spotipy/client.py", line 124, in _internal_call
    headers=r.headers)
spotipy.client.SpotifyException: http status: 400, code:-1 - https://api.spotify.com/v1/me/playlists?limit=10&offset=0:
 Only valid bearer authentication supported

看来我没有正确地将令牌传递给spotipy客户端。例如,self.sp = spotipy.Spotify(auth="random_bullshit")给出了相同的异常。我也尝试过像这样传递令牌auth=self.auth_token['access_token'],结果是一样的。文档中没有说明auth参数应该是什么,我并没有真正理解source code。但我认为这表明auth=self.auth_token['access_token']是正确的做法。在

谢谢!在


Tags: inpyselftokenauthlibusrlocal
1条回答
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1楼 · 发布于 2024-04-19 06:27:21

正如我在上一次编辑中已经指出的那样,auth=self.auth_token['access_token']是正确的,我只是有一个打字错误。无论如何,由于文档中没有太多关于auth参数的说明,这可能会对某些人有所帮助。在

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