slackclient python异步RTM clien

Question

我对python中所有异步的东西都很陌生。在异步slack RTM客户端使用专用回调监听消息时，我想运行一段特定的代码，如下所示：

RTM_CLIENT.start()
    while True:
        ...
except Exception as e:
    ...
finally:
    RTM_CLIENT.stop()

回调函数：

^{pr2}$

RTM_CLIENT.start()函数返回一个future对象。 但我没有收到任何消息事件。我做错什么了吗？在

Answer 1

这就解决了这个问题（线程同步）：

import re
import slack
import time
import asyncio
import concurrent
from datetime import datetime


@slack.RTMClient.run_on(event='message')
async def say_hello(**payload):
    data = payload['data']
    print(data.get('text'))


def sync_loop():
    while True:
        print("Hi there: ", datetime.now())
        time.sleep(5)


async def slack_main():
    loop = asyncio.get_event_loop()
    rtm_client = slack.RTMClient(token='x', run_async=True, loop=loop)
    executor = concurrent.futures.ThreadPoolExecutor(max_workers=1)
    await asyncio.gather(
        loop.run_in_executor(executor, sync_loop),
        rtm_client.start()
    )


if __name__ == "__main__":
    asyncio.run(slack_main())