使用KrakenexPython模块,我从Kraken API获取价格,它以以下格式到达:
{u'result': {u'XXBTZEUR': {u'a': [u'214.79000', u'3'], u'c': [u'214.79416', u'2.27789000'], u'b': [u'214.15262', u'7'], u'h': [u'217.36000', u'217.36000'], u'l': [u'210.99999', u'210.99999'], u'o': u'214.01000', u'p': [u'213.77705', u'213.51830'], u't': [1360, 1499], u'v': [u'872.87753147', u'1036.51819483']}}, u'error': []}
(这是下面代码中'ticker'的输出)
通过字典操作,我可以得到最后的收盘价,在本例中为214.79416:
^{pr2}$直到我把收盘价输入到一个列表中,然后u’s重新出现。以下是完整代码:
from time import strftime
import krakenex
k = krakenex.API()
x = []
y = []
count = 0
while count <= 9:
ticker = k.query_public('Ticker', {'pair': 'XXBTZEUR'})
last_close_raw = ticker["result"]["XXBTZEUR"]["c"]
last_close = last_close_raw[0]
timenow = strftime("%H:%M:%S")
print "%s ----> %s\n----------(%s)" % (timenow, last_close, count)
x.append(count)
y.append(last_close)
count += 1
print "x = ", x
print "y = ", y
这是输出:
23:07:03 ----> 214.79416
----------(0)
23:07:05 ----> 214.79416
----------(1)
23:07:06 ----> 214.79416
----------(2)
23:07:07 ----> 214.79416
----------(3)
23:07:07 ----> 214.79416
----------(4)
23:07:08 ----> 214.79416
----------(5)
23:07:09 ----> 214.79416
----------(6)
23:07:10 ----> 214.79416
----------(7)
23:07:11 ----> 214.79416
----------(8)
23:07:12 ----> 214.79416
----------(9)
x = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
y = [u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416', u'214.79416']
为什么一张单子能把你带回来?我甚至试过从每个价格中删除前两个字符,但这会删除前两个数字,而不是u'。思想?在
困扰您的是Unicode字符串和ASCII字符串之间的差异。要删除
u
,请使用encode
:希望这会有帮助。在
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