avail = range(n_connections)
for i in range(0,n_entities):
for j in range(0,n_connections):
if avail[j] != -1: #checking availability
if (((dat[j][1] == 1)|((dat[j][1] == 11))) & (dat[j][2] == i)):
if ((dat[j][3] == 3)|(dat[j][3] == 13)):
avail[j] = -1 # here error is coming how to fix this
# n_connections = len(connectionx - 1)
for k in range (0,n_connections):
if avail[k] != -1: #checking availability
if (((dat[k][1] == 3)|((dat[k][1] == 13))) & (dat[k][2] == dat[j][4])):
avail[k] = -1 # booking
Tags:
在python2中,
range()
返回一个常规的整数列表,但在python3中不返回。在如果您希望
avail
成为这样一个列表,请执行以下操作:相关问题 更多 >
编程相关推荐