基于lis的字符串加空格

Question

我有一个字符串s和一个字符串列表arr。 s的长度等于arr中字符串的总长度。 我需要将s拆分为一个列表，这样列表中的每个元素的长度都与arr中的相应元素的长度相同。在

例如：

s = 'Pythonisanprogramminglanguage'

arr = ['lkjhgf', 'zx', 'qw', 'ertyuiopakk', 'foacdhlc']

^{pr2}$

Answer 1

将iter与next一起使用会更干净：

s = 'Pythonisanprogramminglanguage'
arr = ['lkjhgf', 'zx', 'qw', 'ertyuiopakk', 'foacdhlc']
new_s = iter(s)
result = [''.join(next(new_s) for _ in i) for i in arr]

输出：

^{pr2}$

Answer 2

使用一个简单的for循环，可以执行以下操作：

s = 'Pythonisanprogramminglanguage'

arr = ['lkjhgf', 'zx', 'qw', 'ertyuiopakk', 'foacdhlc']

start_index = 0
expected = list()
for a in arr:
    expected.append(s[start_index:start_index+len(a)])
    start_index += len(a)

print(expected)

Answer 3

一种方法是：

s = 'Pythonisanprogramminglanguage'

arr = ['lkjhgf', 'zx', 'qw', 'ertyuiopakk', 'foacdhlc']

expected = []
i = 0
for word in arr:
    expected.append(s[i:i+len(word)])
    i+= len(word)

print(expected)