我尝试使用jinja2创建一个if-else条件,其中只有状态为pending_approval
或{for loop
中,所以如果条件为真,并且所有行都有delete按钮,反之亦然。在
非常感谢任何帮助
以下是我的代码:
在模型.py在
class Leave(models.Model):
employee = models.ForeignKey(Employee, on_delete=models.CASCADE, related_name='+')
type = models.ForeignKey(LeavesType, on_delete=models.CASCADE, related_name='+')
status = (('cancelled', 'Cancelled'),
('taken', 'Taken'),
('pending_approval', 'Pending Approval'),
('scheduled', 'Scheduled'),
('weekend', 'Week End'),
('public_holiday', 'Public holiday'),
)
status = models.CharField(max_length=50, choices=status, default='pending_approval')
在视图.py在
^{pr2}$html格式
<table id="Log" class="display table table-hover table-responsive leaves-table">
<thead>
<tr>
<th class="small text-muted text-uppercase"><strong>Leave Type</strong></th>
<th class="small text-muted text-uppercase"><strong>Status</strong></th>
<th class="small text-muted text-uppercase"><strong></strong></th>
</tr>
</thead>
<tbody>
{% for field in leaves_log %}
<tr>
<td>{{field.type}}</td>
<td><img class="media-object img-circle status-icon-size" src="/media/dashboard/ui/file_status/{{field.status}}.png" style="display: inline-block; height: 24px; margin-right: 10px;">{{field.status}}</td>
<td><div class="btn-group">
{% if field.status == 'pending_approval' or 'scheduled'%}
<button type="button" class="btn btn-default btn-xs dropdown-toggle active" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
Action <span class="caret"></span>
</button>
<ul class="dropdown-menu dropdown-menu-right">
<li onclick="delete_leaves();">
<a href="/hrm/employee/{{field.id}}/delete/" onclick="return confirm('Are you sure you want to delete this item?');">
<i class="fa fa-fw fa-trash text-gray-lighter m-r-1"></i>Withdraw
</a>
</li>
</ul>
</div>
</td>
{% else %}
<td></td>
{% endif %}
</tr>
</tbody>
您没有正确使用
or
运算符。它用于分隔两个布尔值,因此您可以想象被解释为
^{pr2}$并且
bool('any non-empty string')
总是True
正确的语法是
或者
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