如何在Django CRUD中自定义auth.User管理页？

Answer 1

假设您的用户类是User，而您的订阅日期字段是subscription_date，这就是您需要在admin.py上添加的内容

class UserAdmin(admin.ModelAdmin):
    list_display = ('subscription_date',)

admin.site.register(User, UserAdmin)

Answer 2

我终于在admin.py文件中这样做了：

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

UserAdmin.list_display = ('email', 'first_name', 'last_name', 'is_active', 'date_joined', 'is_staff')

admin.site.unregister(User)
admin.site.register(User, UserAdmin)

Answer 3

另一种方法是扩展UserAdmin类。

您还可以创建一个函数以显示列表

from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class CustomUserAdmin(UserAdmin):
    def __init__(self, *args, **kwargs):
        super(UserAdmin,self).__init__(*args, **kwargs)
        UserAdmin.list_display = list(UserAdmin.list_display) + ['date_joined', 'some_function']

    # Function to count objects of each user from another Model (where user is FK)
    def some_function(self, obj):
        return obj.another_model_set.count()


admin.site.unregister(User)
admin.site.register(User, CustomUserAdmin)