我从这个question得到了一个python脚本,它将从USGS高程点查询服务中提取。但是,它总是超时,并在一段看似随机的时间之后,在查询完成之前将我踢出。我需要另一种方法来获取给定纬度坐标的高程数据。在
以下是我当前的查询:
# ========= pull elev from usgs server ======
# USGS POINT QUERY SERVICE ==================
url = r'https://nationalmap.gov/epqs/pqs.php?'
# ===========================================
# coordinates with known elevation
lat = [48.633, 48.733, 45.1947, 45.1962]
lon = [-93.9667, -94.6167, -93.3257, -93.2755]
# create df
df = pd.DataFrame({
'lat': lat,
'lon': lon
})
def elevation_function(df, lat_column, long_column):
elevations = []
counter = 0
start = time.time()
for lat, lon in zip(df[lat_column], df[long_column]):
# define rest query params
params = {
'output': 'json',
'x': lon,
'y': lat,
'units': 'Meters'
}
# format query string and return query value
result = requests.get((url + urllib.parse.urlencode(params)))
elevations.append(result.json()['USGS_Elevation_Point_Query_Service']['Elevation_Query']['Elevation'])
counter += 1
print('Proportion of job complete: {}'.format(round(counter/df.shape[0],3)))
end = time.time()
print(str(round(end - start)) + " seconds into job\n")
df['elev'] = elevations
return elevations
start = time.time()
count = 0
for i in range(100):
count += 1
elevations = elevation_function(df, lat_column='lat', long_column='lon')
end = time.time()
print(str(round(end - start)))
简化功能并添加错误处理:
elevation_function
需要编写才能使用{a1}apply
,与axis=1
,自动迭代每一行坐标新功能:
make_remote_request
将继续发出请求,直到它得到response
。在except (OSError, urllib3.exceptions.ProtocolError) as error
)import time
并在异常中的time.sleep(5)
之前添加time.sleep(5)
,以便更好地处理远程服务器。在实现功能
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