我和我的朋友正在用海龟做一个Python游戏。我们的问题是在定义海龟的部分。我们试图加快每只海龟的速度,但当我们这样做时,默认速度运行。为什么会出现这个问题?
import turtle
turtle.setup(1000,1000)
wn=turtle.Screen()
wn.title("Snake Game!")
#defines first turtle
t1=turtle.Turtle()
t1.pensize(2)
t1.speed(3)
t1.penup()
t1.goto(0,100)
t1.color("blue", "blue")
t1.pendown()
#defines second turtle
t2=turtle.Turtle()
t2.pensize(2)
t2.speed(3)
t2.penup()
t2.goto(0,-100)
t2.color("red", "red")
t2.pendown()
#defines outline
ol=turtle.Turtle()
ol.pensize(2)
ol.speed(7)
ol.penup()
ol.goto(450,0)
ol.color("black", "black")
ol.pendown()
ol.left(90)
ol.forward(300)
ol.left(90)
ol.forward(900)
ol.left(90)
ol.forward(600)
ol.left(90)
ol.forward(900)
ol.left(90)
ol.forward(300)
ol.hideturtle()
#defines score
score1=int(2)
score2=int(2)
def motion():
global move, score1, score2
move = True
path1 = []
path2 = []
#prints score
print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")
#defines motion
while move == True:
global pos1x, pos2x
t1.forward(1)
t2.forward(1)
pos1x = int(t1.xcor())
pos1y = int(t1.ycor())
t1xy = (pos1x, pos1y)
pos2x=int(t2.xcor())
pos2y=int(t2.ycor())
t2xy=(pos2x,pos2y)
path1.append(t1xy)
path2.append(t2xy)
#calculates score1
if t1xy in path2:
score1=int(score1-1)
print("")
print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")
t1.clear()
path1 = []
t2.clear()
path2 = []
t1.penup()
t1.goto(0,100)
t1.pendown()
t2.penup()
t2.goto(0,-100)
t2.pendown()
move = False
if score1==0:
print("Player 2 wins!")
exit()
else:
move==True
#calculates score2
if t2xy in path1:
score2=int(score2-1)
print("")
print("Player 1's score is", str(score1)+"!")
print("Player 2's score is", str(score2)+"!")
t2.clear()
path2 = []
t1.clear()
path1 = []
t2.penup()
t2.goto(0,-100)
t2.pendown()
t1.penup()
t1.goto(0,100)
t1.pendown()
move = False
if score2==0:
print("Player 1 wins!")
exit()
else:
move==True
#borders
if pos1x > 450:
t1.left(135)
if pos2x > 450:
t2.left(135)
if pos1x < -450:
t1.left(135)
if pos2x < -450:
t2.left(135)
if pos1y > 300:
t1.left(135)
if pos2y > 300:
t2.left(135)
if pos1y < -300:
t1.left(135)
if pos2y < -300:
t2.left(135)
#defines controls
def left():
t1.speed(500)
t1.left(45)
t1.speed(3)
def right():
t1.speed(500)
t1.right(45)
t1.speed(3)
def backwards():
t1.left(180)
def stop():
global move
move = False
t1.forward(0)
t2.forward(0)
def left2():
t2.speed(500)
t2.left(45)
t2.speed(3)
def right2():
t2.speed(500)
t2.right(45)
t2.speed(3)
def backwards2():
t2.left(180)
def motion2():
move = True
path1 = []
path2 = []
#onkeys
wn.onkey(left2, "Left")
wn.onkey(right2, "Right")
wn.onkey(backwards2, "Down")
wn.onkey(left, "a")
wn.onkey(right, "d")
wn.onkey(backwards, "s")
wn.onkey(motion, "t")
wn.onkey(stop, "y")
wn.onkey(motion2, "p")
wn.listen()
wn.mainloop()
如果只是简单的改变海龟的速度:
海龟是海龟的名字,例如
TestTurtle
数字可以是从
1
到10
,并且必须是一个整数。例如,不能将4.7
作为数字。将其设置为高于
10
将导致速度不起作用。你想在这里发生什么?
将速度设置为高于10(快速)将其设置为0(最快)。一旦手术完成,你就把它设为3(慢)。
据我所知,你可以暂时加快海龟们的行动,而不是从中得到太多,例如
left()
,但让海龟们在^{慢的行动,应该受益于它的速度,例如motion()
我建议您退出所有的
speed()
调用并重新考虑它们,最好使用字符串参数“slowest”、“slow”、“normal”、“fast”来帮助记录您正在做的事情并避免超出范围。把海龟的速度设定在10以上是没有意义的。 如果不使用动画,请将速度设置为0:speed(0)。否则使用速度(10)。
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