Python倒计时游戏需要贵丹

Question

我正在创建一个python倒计时程序，但是遇到了问题。在

这是我的代码：

import time

def countdown(count):
    while (count >= 0):
        print ("Time remaining: "+ str(count) + " seconds")
        count -= 1
        time.sleep(1)

countdown(120)
print("Times up!")
time.sleep(3)

我得到的输出是：

^{pr2}$

我想改变程序的输出时间：

You have 2 minutes and 2 seconds remaining.
You have 2 minutes and 1 seconds remaining.
You have 2 minutes and 0 seconds remaining.
You have 1 minutes and 59 seconds remaining.

等等。在

如何转换？在

Answer 1

将打印时间的行改为：

print("You have {} minutes and {} seconds remaining.".format(*divmod(count, 60)))

---

以下是全文：

^{pr2}$

以及一个示例：

Welcome. This program will put your computer to sleep in 5 minutes.
To abort shutdown, please close the program.

You have 2 minutes and 0 seconds remaining.
You have 1 minutes and 59 seconds remaining.
You have 1 minutes and 58 seconds remaining.
You have 1 minutes and 57 seconds remaining.
You have 1 minutes and 56 seconds remaining.
You have 1 minutes and 55 seconds remaining.
...

---

最后，这里有一个关于^{}和一个关于{a2}的引用。在

Answer 2

每次迭代需要睡眠1秒，因此count是剩余的秒数。在

分钟数是count / 60，剩余秒数是count % 60（模）。所以你可以写一些

mins = count / 60
secs = count % 60

print "Time remaining is %d minutes %d seconds" % (mins, secs)

您可以在一次操作中同时计算分钟和秒mins, secs = divmod(count, 60)。在

请注意，sleep()并不精确；它只保证程序的睡眠时间不少于指定的数量。您会注意到，有时程序的暂停时间比挂钟少几秒钟。在

如果您想要更高的精度，您应该计算循环结束的最终时间，检查每次迭代的当前时间，并显示它们之间的实际差异。在