如何让Python复利计算器给出正确的答案

Question

早前曾发布过一个关于错误的问题。多亏了这里的几个人，我才解决了这个问题。现在我遇到了我的复利计算器的问题，当你输入本金、复利（年、月等）、利率（0.03等）和年数时，计算错误。 其他Q链接：final = P * (((1 + (r/n)) ** (n*t))) TypeError: unsupported operand type(s) for /: 'str' and 'int' 所以在前面的代码中，我去掉了p=10000，n=12，r=0.08，因为当你输入不同的数字时，它会给出一个很大的数字。我希望它能用输入的数字来计算，但事实并非如此

# User must input principal, Compound rate, annual rate, and years.
P = int(input("Enter starting principle please. "))
n = int(input("Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) "))
r = float(input("Enter annual interest amount. (decimal) "))
t = int(input("Enter the amount of years. "))

final = P * (((1 + (r/n)) ** (n*t)))
#displays the final amount after number of years.
print ("The final amount after", t, "years is", final)
# At the moment it is displaying a very random number.

Enter starting principle please. 1000
Enter Compound intrest rate.(daily, monthly, quarterly, half-year, yearly) 1
Enter annual interest amount. (decimal) 0.01
Enter the amount of years. 1
The final amount after 1 years is 1010.0

最终金额应为1000.10。不知道发生了什么。试着看看是否有办法使P，n，r等于用户输入的数字，从而得到正确的最终答案。

提前谢谢。

Answer 1

基于此： 复利公式 FV=P（1+r/n）^Yn， 其中P是起始本金，r是年利率，Y是投资年数，n是每年复利期数。FV是未来价值，意味着本金在Y年后增长到的金额。

P = int(input("Enter starting principle please. "))
n = int(input("Enter number of compounding periods per year. "))
r = float(input("Enter annual interest rate. e.g. 15 for 15% "))
y = int(input("Enter the amount of years. "))

FV = P * (((1 + ((r/100.0)/n)) ** (n*y)))

print ("The final amount after", y, "years is", FV)

Answer 2

如果你对百分比感兴趣，你应该在代码中处理。

final = P * (((1 + (r/(100.0 * n))) ** (n*t)))

Answer 3

请尝试以下复利的Python代码：

p = float(input('Please enter principal amount:'))
t = float(input('Please enter number of years:'))
r = float(input('Please enter rate of interest:'))
n = float(input('Please enter number of times the interest is compounded in a year:'))
a = p*(1+(r/(100*n))**(n*t))
print('Amount compounded to: ', a)