python列表.索引如果字符串在列表[0]中，（''）无法在列表中找到字符串为什么？我怎么找到它？

Question

我疯了吗？在

在我的测试中python列表.索引如果字符串在列表[0]中，（''）在列表中找不到字符串！！！在

为什么？我怎么找到它？在

下面是我的示例代码：

list1 = ['WTF', '2.09', '\xc2\x80document.write(CurrencyFormat(Currency.convert((209/100),"GBP","EUR")));','0.00', 'Feminised', '6.88', '\xc2\x80document.write(CurrencyFormat(Currency.convert((688/100),"GBP","EUR")));', 'Regular', 'x10', '20.90', '\xc2\x80document.write(CurrencyFormat(Currency.convert((2090/100),"GBP","EUR")));', 'Feminised', 'x12', '82.56', '\xc2\x80document.write(CurrencyFormat(Currency.convert((8256/100),"GBP","EUR")));']
list2 = ['1','2','3','4','5', '1']
if list1.index('0.00'):
    print "I found 0.00 in list 1 but if its in position[0], I cannot find it using index('0.00') - even it appears twice what gives?"
if list2.index('1'):
    print 'weird'
else:
    print 'I did not find 1 in list 2 even thought it is definitely there (twice infact)... WTF?'
print 'I can find it like this but I want to search by string >>> ' + list2[0]
print 'Or like this like this but I want to search by string >>> ' + list2[-1]

结果如下：

^{pr2}$

我想我一定错过了一些很明显的东西。。。但无法找到答案。。。请帮助我通过搜索字符串在列表1中查找“WTF”或在列表2中查找“1”。。。。。在

Answer 1

当您执行if list1.index('1')操作时，您正在测试该列表中'1'的索引是否为布尔真。它的索引为零，这是布尔值false。所以你的if块不运行。在

如果你想知道它是否在里面，只要做if '1' in list1。在