我正在研究Project Euler问题5,并使用以下方法:
def findLCM(k):
start=time.time()
primes=[2,3,5,7,11,13,17,19,23]
factors=[]
for factor in range(2,k):
if factor in primes:
factors.append(factor)
else:
factorization=[]
while factor!=1:
for prime in primes:
lastFactor=prime
if factor%prime==0:
factor/=prime
factorization.append(lastFactor)
break
tmpFactors=[]
for tmpFactor in factorization:
if tmpFactor not in factors:
factors.append(tmpFactor)
else:
tmpFactors.append(tmpFactor)
factors.remove(tmpFactor)
for tmpFactor in tmpFactors:
factors.append(tmpFactor)
print factors
product=1
for factor in factors:
product*=factor
factors.sort()
end=time.time()
fnTime=end-start
return product, fnTime, factors
有没有一个Python函数可以像这个函数那样把因子分解和因子结合起来?例如,如果factors=[2, 3, 5]
和factorization=[2, 2, 3]
,组合的列表应该是[2, 2, 3, 5]
。在
术语是multisets的并集。在
它在Python中使用collections.Counter实现:
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