如何使用Python从URL中删除查询字符串

Question

示例：

http://example.com/?a=text&q2=text2&q3=text3&q2=text4

删除“q2”后，它将返回：

http://example.com/?q=text&q3=text3

在本例中，存在多个“q2”，并且都已删除。

Answer 1

import sys

if sys.version_info.major == 3:
    from urllib.parse import urlencode, urlparse, urlunparse, parse_qs
else:
    from urllib import urlencode
    from urlparse import urlparse, urlunparse, parse_qs

url = 'http://example.com/?a=text&q2=text2&q3=text3&q2=text4&b#q2=keep_fragment'
u = urlparse(url)
query = parse_qs(u.query, keep_blank_values=True)
query.pop('q2', None)
u = u._replace(query=urlencode(query, True))
print(urlunparse(u))

输出：

http://example.com/?a=text&q3=text3&b=#q2=keep_fragment

Answer 2

import cgi
import urlparse
url = "http://example.com/?a=text&q2=text2&q3=text3&q2=text4"
qs = cgi.parse_qs(urlparse.urlparse(url)[4])
del(qs['q2'])
print qs

明确。。。

>>> import cgi
>>> import urlparse
>>> url = "http://example.com/?a=text&q2=text2&q3=text3&q2=text4"
>>> qs = cgi.parse_qs(urlparse.urlparse(url)[4])
>>> del(qs['q2'])
>>> print qs
{'a': ['text'], 'q3': ['text3']}
>>>

Answer 3

要删除所有查询字符串参数，请执行以下操作：

from urllib.parse import urljoin, urlparse

url = 'http://example.com/?a=text&q2=text2&q3=text3&q2=text4'
urljoin(url, urlparse(url).path)  # 'http://example.com/'

对于Python2，将导入替换为：

from urlparse import urljoin, urlparse