"Google日曆活動D格式化"

Question

我正在使用Python Google日历APi。在

代码：

import datetime
from googleapiclient.discovery import build
from httplib2 import Http
from oauth2client import file, client, tools
# If modifying these scopes, delete the file token.json.
SCOPES = 'https://www.googleapis.com/auth/calendar.readonly'


def main():
    """Shows basic usage of the Google Calendar API.
    Prints the start and name of the next 10 events on the user's calendar.
    """
    # The file token.json stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    store = file.Storage('token.json')
    creds = store.get()
    if not creds or creds.invalid:
        flow = client.flow_from_clientsecrets('credentials.json', SCOPES)
        creds = tools.run_flow(flow, store)
    service = build('calendar', 'v3', http=creds.authorize(Http()))

    # Call the Calendar API
    now = datetime.datetime.utcnow().isoformat() + 'Z'  # 'Z' indicates UTC time
    print('Getting the upcoming 10 events')
    events_result = service.events().list(calendarId='primary', timeMin=now,
                                          maxResults=10, singleEvents=True,
                                          orderBy='startTime').execute()
    events = events_result.get('items', [])

    if not events:
        print('No upcoming events found.')
    for event in events:
        start = event['start'].get('dateTime', event['start'].get('date'))
        print(start, event['summary'])


if __name__ == '__main__':
    main()

如果运行，输出如下所示：

^{pr2}$

据我所知，这是ISO格式。问题是，我找不到一种方式来将时间格式化为像“12月26日，10:00”这样的人。在

我试过很多东西。 我不能使用.strftime(), .strptime()或dateutil.parser

最有希望的是： 变量=日期时间.日期时间.strptime（现在，'%Y-%m-%d%H:%m:%S.%f'）。strftime（“%B%d，%Y”），但是我得到了这个错误。。在

值错误：时间数据“2018-12-13T11:56:31.095470Z”与格式“%Y-%m-%d%H:%m:%S.%f”不匹配

我在网上搜索过，但只找到一个unanswered question

Answer 1

您可以使用dateutil.parser和datetime.datetime.strftime一起使用。

from dateutil.parser import parse as dtparse
from datetime import datetime as dt

start = '2018-12-26T10:00:00+01:00'   # Let's say your start value returns this as 'str'
tmfmt = '%d %B, %H:%M %p'             # Gives you date-time in the format '26 December, 10:00 AM' as you mentioned

# now use the dtparse to read your event start time and dt.strftime to format it
stime = dt.strftime(dtparse(start), format=tmfmt)

输出：

^{pr2}$

然后使用下面的命令打印事件。

^{3}$