Leetcode Python问题

Question

在试图解决LeetCode的几个问题时，我遇到了一个非常奇怪的问题。在

Question 26: Remove Duplicates from Sorted Array

https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/

Example:

Given nums = [1,1,2],

Your function should return length = 2, with the first two elements of 
nums being 1 and 2 respectively.
It doesn't matter what you leave beyond the new length.

为了对这个问题进行编码，我使用了：

^{pr2}$

what this code is doing is first converting the list into a set and then back to list, which in turn will remove the Duplicates

但是当我试图将此代码提交给leetcode解决方案时，会返回nums的modified length，但是当程序试图访问nums数组时，它不会被更新。在

This is only Happening in Leetcode editor, in my system If I try to print the nums, the modified value is displayed, not sure what is wrong.

现在同样的情况也发生在其他问题上，例如：

Rotate Array https://leetcode.com/explore/interview/card/top-interview-questions-easy/92/array/646/

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

我对这个问题的解决办法如下：

class Solution(object):
 def rotate(self, nums, k):
    newIndex = k % len(nums)
    nums = nums[newIndex+1:len(nums)] + nums[0:newIndex+1]
    print nums

但我再次惊讶于我从提交文件中得到的结果。在

Note Here in the "Your STDOUT" we can see the list is modified accordingly. link to the Screenshot

请让我知道，如果有人面临这个问题，或有人知道这个问题的解决办法。在

Answer 1

你可以用 sudo service network-manager restart

Answer 2

代码中发生的是返回的长度被用于在后端遍历nums，以打印nums列表的唯一值。所以，问题的关键是返回的长度将从索引0移动到返回的长度。因此，在返回唯一值的长度时，我们还必须修改原始列表，即nums。 第一条链路的解决方案

class Solution:
    def removeDuplicates(self, nums):
        if(len(nums) == 0):
            return 0
        elif len(nums) == 1 :
            return 1
        else:
            l = 1
            for i in range (1,len(nums)):
                if nums[i] != nums[i-1] :
                    #l+=1
                    nums[l] = nums[i]
                    l+=1
            return l

Answer 3

原来解决这个问题的方法是使用：nums[:] = nums[newIndex+1:len(nums)] + nums[0:newIndex+1]。在

执行nums = nums[newIndex+1:len(nums)] + nums[0:newIndex+1]只会更改引用，而nums[:]会更改列表的值。在