考虑测试中的代码:
import pika
class MQ_Client():
connection = None
channel = None
exchange_name="my_exchange"
def connect(self):
self.connection = pika.BlockingConnection(pika.ConnectionParameters(host="mq_server")
def publish(self, message):
properties = pika.BasicProperties(content_type='text/json', delivery_mode=1)
if self.channel.basic_publish(exchange=self.exchange_name, routing_key='', properties=properties, body=message):
log.info("Successfully published this message to exchange \"" + self.exchange_name + "\": " + message)
else:
log.error("Failed to publish message \"" + message + "\" to the exchange \"" + self.exchange_name + "\"!")
raise Exception("Failed to publish message to the queue.")
我想要的是修补Pika的basic_publish
方法来引发一个异常,并可能需要一些帮助来找出如何做到这一点。这是我最后一次尝试:
任何关于如何让这个工作的建议将不胜感激!在
我成功了。模拟实例方法与模拟类方法完全不同。在阅读了this excellent article之后,我终于明白了如何做到这一点,结果发现我所需要的修补
basic_publish
方法只需稍微修改一下我的测试,如下所示:相关问题 更多 >
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