在python中将二进制文件转换为utf-8

Question

我有一个这样的二进制： 1101100110000110110110011000001011011000101001111101100010101000

我想把它转换成utf-8。 我怎么能用python做这个？

Answer 1

>>> s='1101100110000110110110011000001011011000101001111101100010101000'
>>> print (''.join([chr(int(x,2)) for x in re.split('(........)', s) if x ])).decode('utf-8')
نقاب
>>> 

或者，相反：

>>> s=u'نقاب'
>>> ''.join(['{:b}'.format(ord(x)) for x in s.encode('utf-8')])
'1101100110000110110110011000001011011000101001111101100010101000'
>>> 

Answer 2

清洁剂版本：

>>> test_string = '1101100110000110110110011000001011011000101001111101100010101000'
>>> print ('%x' % int(test_string, 2)).decode('hex').decode('utf-8')
نقاب

反面（摘自@Robᵩ的评论）：

>>> '{:b}'.format(int(u'نقاب'.encode('utf-8').encode('hex'), 16))
1: '1101100110000110110110011000001011011000101001111101100010101000'