python 2.7字符\u2013

Question

我有以下代码：

# -*- coding: utf-8 -*-

print u"William Burges (1827–81) was an English architect and designer."

当我试图从命令运行它时。我收到以下信息：

Traceback (most recent call last):
  File "C:\Python27\utf8.py", line 3, in <module>
    print u"William Burges (1827ŌĆō81) was an English architect and designer."
  File "C:\Python27\lib\encodings\cp775.py", line 12, in encode
    return codecs.charmap_encode(input,errors,encoding_map)
UnicodeEncodeError: 'charmap' codec can't encode character u'\u2013' in position
 20: character maps to <undefined>

如何解决此问题并使Python读取此字符？为什么Python没有用现有的代码来读取它，我认为utf-8对每个字符都有效。

谢谢你

编辑：

这段代码打印出想要的结果：

# -*- coding: utf-8 -*-

print unicode("William Burges (1827-81) was an English architect and designer.", "utf-8").encode("cp866")

但当我尝试打印多个句子时，例如：

# -*- coding: utf-8 -*-

print unicode("William Burges (1827–81) was an English architect and designer. I am here. ", "utf-8").encode("cp866")

我收到相同的错误消息：

Traceback (most recent call last):
  File "C:\Python27\utf8vs.py", line 3, in <module>
    print unicode("William Burges (1827ŌĆō81) was an English architect and desig
ner. I am here. ", "utf-8").encode("cp866")
  File "C:\Python27\lib\encodings\cp866.py", line 12, in encode
    return codecs.charmap_encode(input,errors,encoding_map)
UnicodeEncodeError: 'charmap' codec can't encode character u'\u2013' in position
 20: character maps to <undefined>

Answer 1

我怀疑问题出在print语句上，而不是python本身（它在我的Mac上运行得很好）。为了打印字符串，它需要将其转换为可显示的格式；在Windows命令行的默认字符集中，您使用的长划线不可显示。

你两个句子的区别不在于长度，而在于（1827-81）“vs”（1827-81）“中使用的破折号——你能看出细微的区别吗？尝试复制和粘贴一个到另一个检查这个。

另请参见Python, Unicode, and the Windows console。

Answer 2

实际上wiki.python.org上有一篇关于这个问题的wiki文章https://wiki.python.org/moin/PrintFails，解释了为什么使用charmap编解码器可能会发生这种情况。

Setting the PYTHONIOENCODING environment variable as described above can be used to suppress the error messages. Setting to "utf-8" is not recommended as this produces an inaccurate, garbled representation of the output to the console. For best results, use your console's correct default codepage and a suitable error handler other than "strict".

Answer 3

您的字符串包含ndash sumbol。它类似于ascii减号-，请参见符号45 an ascii table。将ndash替换为减号，因为ascii不能包含ndash。以下工作变型：

# -*- coding: utf-8 -*-

my_string = "William Burges (1827–81) was an English architect and designer."
my_string = my_string.replace("–", "-")# replace utf-8 symbol (ndash) to ascii (-)
print my_string

输出

William Burges (1827-81) was an English architect and designer. I am here.