urllib2.urlopen('ur')给出

2024-03-29 12:29:34 发布

您现在位置:Python中文网/ 问答频道 /正文

我是python新手,正在尝试提取页面的内容。当我执行urlopen('http://www.google.com')操作时,我得到以下错误:

File "<stdin>", line 1, in <module>    
  File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/usr/lib/python2.7/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.7/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.7/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/python2.7/urllib2.py", line 1185, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/usr/lib/python2.7/urllib2.py", line 1160, in do_open
    raise URLError(err)

有什么解决办法吗?在


Tags: inpyselfhttpdatareturnlibusr