链接到DetailVi时出现Django NoReverseMatch错误

Question

我很难从记者的主视图链接到我的详细视图。两个URL都可以。我知道这个问题有很好的文档记录，但是url非常混乱，我似乎找不到解决方案。 这是我的密码视图.py, 表格.py（错误是由于此中的一行导致的），网址.py. 在

我们将不胜感激。 链接是/reporters/which should link to/reporters/pk/detail `在

tables.py 
    import django_tables2 as tables
from django_tables2.utils import A
from models import Reporter

class ReporterTable(tables.Table):
    #my error is on the next time. It works for #list_all but not detail. 
    id = tables.LinkColumn('mysite.apps.reporters.views.detail', args=[A('pk')])
    class Meta:
        model = Reporter
        attrs = {"class": "paleblue"}
        fields = ('id', 'surname', 'othername', 'gender')

class ReporterViewTable(tables.Table):
    class Meta:
        model = Reporter
        attrs = {"class": "paleblue"}

views.py
from django.shortcuts import render
from django.http import HttpResponse
from django.template import RequestContext, loader
from django.views.generic.detail import DetailView
from django_tables2 import RequestConfig
from tables import ReporterTable, ReporterViewTable

from models import Reporter

class ReporterDetailView(DetailView):
    model = Reporter

    def get_context_data(self, **kwargs):
        context = super(ReporterDetailView, self).get_context_data(**kwargs)
        return context

def index(request):
    table = ReporterTable(Reporter.objects.all())
    RequestConfig(request).configure(table)
    return render(request, 'reporters/index.html', {'table':table})

urls.py

from django.conf.urls import patterns, include, url

from django.views.generic import DetailView, ListView
from views import ReporterDetailView

urlpatterns = patterns('mysite.apps.reporters.views',
    url(r'^$', 'index'), 
    url(r'^list_all/$', 'list_all'), 
    url(r'^(?P<pk>\d+)/detail/$', ReporterDetailView.as_view(template_name='reporters/detail.html')),
    url(r'^(?P<reporter_id>\d+)/edit/$', 'edit'),

)

index.html

{% load staticfiles %}
{% load render_table from django_tables2 %}
<link rel="stylesheet" type="text/css" href="{% static 'reporters/style.css' %}" />
{% if table %}
<div>
    {%render_table table %}
</div>
{% else %}
    <p>No Reporters are available.</p>
{% endif %}

非常感谢！在

这是完整的异常头。在

^{pr2}$

整个异常都在这个粘贴箱here中。在

Answer 1

对于直接导入的基于类的视图，您需要为视图指定一个名称，以便从其他位置引用它：

在网址.py在

urlpatterns = patterns('mysite.apps.reporters.views',
    url(r'^$', 'index'), 
    url(r'^list_all/$', 'list_all'), 
    url(r'^(?P<pk>\d+)/detail/$', ReporterDetailView.as_view(template_name='reporters/detail.html'), name='reporter_detail'),
    url(r'^(?P<reporter_id>\d+)/edit/$', 'edit'),

）

然后在您的ReporterTable中：

^{pr2}$

Answer 2

args应该是一个元组，因此类似这样的内容而不是列表：

id = tables.LinkColumn('mysite.apps.reporters.views.detail', args=(A('pk'),))