学生评分逻辑

Question

我正在解决一个简单的hackerrank问题来给学生评分。我用python编写了代码，但代码逻辑似乎不正确，因为预期的输出没有出现。在

https://www.hackerrank.com/challenges/grading/problem在这里，您可以找到问题陈述。在

问题是

HackerLand University has the following grading policy: Every student receives a grade in the inclusive range from 0 to 100 . Any less than 40 is a failing grade.

Sam is a professor at the university and likes to round each student's grade according to these rules: If the difference between the grade and the next multiple of 5 is less than 3, round up to the next multiple of 5. If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade. For example, grade = 84 will be rounded to 85 but grade = 29 will not be rounded because the rounding would result in a number that is less than 40.

Given the initial value of grade for each of Sam's students, write code to automate the rounding process.

def gradingStudents(grades):
    #
    # Write your code here.
    #
    for x,i in enumerate(grades):
     if(i>=38) and (i%5)>=3:
        grades[x]=i+5-(i%5)
     return (grades)

这是我写的代码。在

输入

^{pr2}$

我的输出是

75, 67, 38, 33

但预期是38应该四舍五入到40

Answer 1

问题是一旦处理完第一个数字，return。 相反，请等到您处理完所有问题：

def gradingStudents(grades):

    for x,i in enumerate(grades):
        if(i>=38) and (i%5)>=3:
            grades[x]=i+5-(i%5)
    return (grades)

book = [73, 67, 38, 33]
print(gradingStudents(book))

输出：

^{pr2}$

Answer 2

你的问题是由于缩进。在

请注意，return语句与if语句对齐，它们都在循环中。因此，您的代码实际上只检查第一个元素，然后返回等级，可能只更改第一个等级。在

一旦您取消了return语句的缩进，使其脱离for循环，您的代码就可以工作了。在