对于课堂作业,我尝试做一个猜数游戏,在这个游戏中,用户决定答案和猜测次数,然后在有限的圈数内猜测数字。我应该使用while循环和and运算符,但不能使用break。然而,我的问题是,我不确定如何格式化程序,以便当达到最大圈数时,程序不会打印提示(高/低),而只会告诉你你丢失了/答案是什么。如果我选择将最大猜测数设为1,它就不起作用了。它不只是打印“You lose;the number was uuu”,它还会打印一个提示。这是我最好的尝试,接近于做这个程序应该做的一切。我做错什么了?在
answer = int(input("What should the answer be? "))
guesses = int(input("How many guesses? "))
guess_count = 0
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
while guess != answer and guess_count < guesses:
guess = int(input("Guess a number: "))
guess_count += 1
if answer < guess:
print("The number is lower than that.")
elif answer > guess:
print("The number is higher than that")
if guess_count >= guesses and guess != answer:
print("You lose; the number was " + str(answer) + ".")
if guess == answer:
print("You win!")
像这样的怎么样?在
它非常类似于您的程序,但是其中有两个
break
语句。这将告诉Python立即停止执行该循环并转到下一个代码块(在本例中为空)。这样,在开始下一个循环之前,您不必等待程序评估为while
循环指定的条件。如果这有助于解决你的问题,那就请你在我的帖子上打勾相关问题 更多 >
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