在列表中查找最大值，即lis中对象的属性

Question

我正在用python3编写一个程序，它可以模拟不同玩家之间的比赛，这些人正在投球。在

我有一个包含players对象的列表，这些对象有属性名称、抛出的平均长度、抛出的标准偏差，最后：一个列表的属性，其中每个索引都包含玩家在每次比赛中进行的多次投掷。（为了澄清，在索引0上，例如第一次比赛有6次投掷，在索引1中，第二次比赛有6次投掷，依此类推）。当然有很多玩家。我现在需要找到一种方法来确定哪一个玩家是每场比赛的赢家，并计算每个玩家的获胜次数。我一直在寻找赢家，但到目前为止，我的想法是：

def winner(self):
    for player in players:
        winner= max(players, key = attrgetter("self.results"))

播放器对象是通过这个类创建的：

^{pr2}$

我很肯定我上面写的东西不会给我带来任何好处，所以你们有什么建议吗？在

Answer 1

这里有一个简化的Player类来帮助您入门。它处理的是一个以上的球员投球的最长距离与另一个相同。在

class Player:
    def __init__(self, name, results):
        self.name = name
        self.results = results

def find_winners(players, num_contests):
    winners = []  # one (or more) player entries per contest
    for icontest in range(num_contests):
        contest_winners = []  # may hold multiple players if there are ties
        contest_longest_throw = -1
        for player in players:
            player_longest_throw = max(player.results[icontest])
            if player_longest_throw > contest_longest_throw:
                contest_longest_throw = player_longest_throw
                contest_winners = [player]
            elif player_longest_throw == contest_longest_throw:
                contest_winners.append(player)
        winners.append(contest_winners)
    return winners

# test data
players = [Player('Name1', [(7, 8, 9), (2, 3, 4), (3, 4, 5)]),
           Player('Name2', [(4, 5, 6), (8, 9, 10), (6, 7, 8)]),
           Player('Name3', [(1, 2, 3), (5, 6, 7), (9, 10, 11)]),
           # add one that will tie with first player
           Player('Name4', [(7, 8, 9), (2, 3, 4), (3, 4, 5)])]

# assumes length of first player's results is number of contests
winners_found = find_winners(players, len(players[0].results))

print("Contest  Winner(s)")
for icontest, contest_winners in enumerate(winners_found, start=1):
    print('{:^7}  {}'.format(
        icontest, ', '.join(player.name for player in contest_winners)))

输出：

^{pr2}$