Python课程梯度

Question

我在为课程评分员写代码。要求是

“如果平均成绩大于或等于70，并且没有一个测试分数低于50，则返回一条消息“通过”。 如果平均分数低于70或至少有一个测试分数低于50，则返回“失败”消息

一旦它确定了平均值，它就给出了通过/失败语句。我没看到什么？在

下面是我写的代码：

def course_grader(test_scores):
    average = sum(test_scores)/len(test_scores)
    if average >= 70:
        return "pass"
    else: 
        return "fail"   

def main():
    print(course_grader([100,75,45]))     # "fail"
    print(course_grader([100,70,85]))     # "pass"
    print(course_grader([80,60,60]))      # "fail"
    print(course_grader([80,80,90,30,80]))  # "fail"
    print(course_grader([70,70,70,70,70]))  # "pass"

if __name__ == "__main__":
    main()

Answer 1

您不需要检查测试分数是否大于或等于50，为此，请使用all()函数在一行中评估所有测试分数的条件，如下所示：

def course_grader(test_scores):
    average = sum(test_scores)/len(test_scores)
    # every ts (test score) must be greater than or equal to 50
    if average >= 70 and all(ts >= 50 for ts in test_scores):
        return "pass"
    else: 
        return "fail

Answer 2

您还可以检查测试分数的min是否大于或等于50。在

def course_grader(test_scores):
    average = sum(test_scores)/len(test_scores)
    if average >= 70 and min(test_scores) >= 50:
        return "pass"
    else: 
        return "fail"