同时使用原始输入创建一个无限循环

Question

在这些行中：

foo = []

a = foo.append(raw_input('Type anything.\n'))
b = raw_input('Another questions? Y/N\n')

while b != 'N':
    b = foo.append(raw_input('Type and to continue, N for stop\n'))
    if b == 'N': break

print foo

如何断环？ 谢谢！在

Answer 1

在列表.追加不返回。在

a = raw_input('Type anything.\n')
foo = [a]
b = raw_input('Another questions? Y/N\n')

while b != 'N':
    b = raw_input('Type and to continue, N for stop\n')
    if b == 'N': break
    foo.append(b)

Answer 2

这就是方法

foo = []

a = raw_input('Type anything.\n')
foo.append(a)
b = raw_input('Another questions? Y/N\n')

while b != 'N':
    b = raw_input('Type and to continue, N for stop\n')
    if b == 'N': break
    foo.append(raw_input)

print foo

Answer 3

{cd1>添加到最后一个元素的检查：

while b != 'N':
    foo.append(raw_input('Type and to continue, N for stop\n'))
    if foo[-1] == 'N': break   # <---- Note foo[-1] here