擅长:python、mysql、java
<p>我无法在python2.7或python3.2中复制您的问题:</p>
<pre><code>>>> import datetime
>>> today = datetime.date(2013, 3, 11)
>>> print today
2013-03-11
>>> day = datetime.timedelta(days=1)
>>> print today - day
2013-03-10
</code></pre>
<p>在我看来,这已经是“日光节约保险箱”<code>yesterday()</code>功能的最简单实现。</p>