我正在制作一个程序来完成certain python challenge。我创建了这个程序,它基本上完成了我需要它做的一切,除了它有一个奇怪的怪癖;它打印我想要的输出多次。在
cmdname = input("Enter the name of your command.\n>")
print("Enter options one by one. If the option has an argument, put a * at the end of the option. When done entering options, enter \"q\".")
oplist = ""
oplist += cmdname + " "
def prgm():
global oplist
while 2 + 2 == 4:
user = input(">")
if user[0] == "-":
if "*" in user:
oplist += user[0:len(user) - 1] + " "
print("Now, enter the option's argument.")
user = input(">")
oplist += user[0:len(user) - 1] + " "
print("Option successfully added.")
prgm()
else:
oplist += user + " "
print("Option successfully added.")
prgm()
elif user == "q":
print("Enter the command argument.")
user = input(">")
oplist += user
else:
print("Error. You didn't enter an option.")
prgm()
break
print(oplist)
prgm()
输出的打印次数似乎取决于用户指定了多少个选项,但我不知道为什么。另外,在IDLE中运行程序时,如果我在函数完成后手动打印(oplist),IDLE会像我希望的那样在一行上打印一次输出。为什么会这样?在
将
print(oplist)
移出函数,移到程序的最后一行。因为您使用递归,所以这行被多次调用。在相关问题 更多 >
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