我有一个示例代码:
# some imports that I'm not including in the question
class daemon:
def start(self):
# do something, I'm not including what this script does to not write useless code to the question
self.run()
def run(self):
"""You should override this method when you subclass Daemon.
It will be called after the process has been daemonized by
start() or restart().
"""
class MyDaemon(daemon):
def run(self):
while True:
time.sleep(1)
if __name__ == "__main__":
daemonz = MyDaemon('/tmp/daemon-example.pid')
daemonz.start()
def firstfunction():
# do something
secondfunction()
def secondfunction():
# do something
thirdfunction()
def thirdfunction():
# do something
# here are some variables set that I am not writing
firstfunction()
如何从类“daemon”的run(self)函数中退出并继续执行firstfunction(),就像在最后一行中所写的那样?我是Python的新手,我正在努力学习
#编辑 我设法将daemon类实现到treading类中。但我的情况与第一个相同,脚本保持在daemon类中,不执行其他行。在
^{pr2}$
您可以使用
break
关键字退出循环,然后继续下一行。return
可用于退出函数。在如果希望MyDaemon与其余代码一起运行,则必须使其成为进程或线程。当MyDaemon类(线程/进程)运行时,代码自动继续到下一行。在
^{pr2}$此代码生成以下结果:
要使
thread
成为守护程序,可以使用thread.setDaemon(True)
。必须在启动线程之前调用该函数:相关问题 更多 >
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