将字典按键值进行排序

Question

我想对可能有int或tuple作为键的字典进行双重排序。在

d = {33:1, 44:1, (0,5):1  12:2, (1,2):2}

我希望它首先按值排序，然后按键排序（如果可能，不是一个是元组，第二个是int）。在

有人能帮我吗？在

提前谢谢

Answer 1

这个怎么样？在

>>> d = {33:1, 44:1, (0,5):1, 12:2, (1,2):2}
>>> helper_dict = {}
>>> for k,v in d.items():
        helper_dict.setdefault(v,[]).append(k)    

>>> sorted_items = [(k,i) for k in sorted(helper_dict.keys()) for i in sorted(helper_dict[k]) ]
>>> sorted_items
[(1, 33), (1, 44), (1, (0, 5)), (2, 12), (2, (1, 2))]

Answer 2

>>> d = {33:1, 44:1, (0,5):1, 12:2, (1,2):2}
>>> {k:v for k,v in sorted(d.items(), key=lambda v: v[::-1])}
{(1, 2): 2, 33: 1, 44: 1, (0, 5): 1, 12: 2}
>>> from collections import OrderedDict
>>> OrderedDict({k:v for k,v in sorted(d.items(), key=lambda v: v[::-1])})
OrderedDict([((1, 2), 2), (33, 1), (44, 1), ((0, 5), 1), (12, 2)])
>>> sorted(d.items(), key=lambda v: v[::-1])
[(33, 1), (44, 1), ((0, 5), 1), (12, 2), ((1, 2), 2)]

Answer 3

或者只是

sorted(d.items(), key=lambda v: v[::-1])

编辑： 因为OP需要结果作为字典

^{pr2}$