所以在Python3
im中使用pygame
,到目前为止,我得到了这个error
这是他的代码,我会加上一个问题所在
import pygame
import time
import random
pygame.init()
display_width = 800
display_height = 600
black = (0,0,0)
white = (255,255,255)
red = (255,0,0)
green = (0,255,0)
car_width = 73
gameDisplay = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption('drivin meh truck-by me')
clock = pygame.time.Clock()
carImg = pygame.image.load('truck.png')
def things(thingx, thingy, thingw, thingh, color):
pygame.draw.rect(gameDisplay, color,[thingx, thingy, thingw, thingh]) #this is were i get the error
def car(x,y):
gameDisplay.blit(carImg,(x,y))
def text_objects(text, font):
textSurface = font.render(text, True, green)
return textSurface, textSurface.get_rect()
def message_display(text):
LargeText = pygame.font.Font('freesansbold.ttf',80)
TextSurf, TextRect = text_objects(text,LargeText)
TextRect.center = ((display_width/2),(display_height/2))
gameDisplay.blit(TextSurf, TextRect)
pygame.display.update()
time.sleep(2)
game_loop()
def crash():
message_display('you done goofed')
def game_loop():
x = (display_width * 0.45)
y = (display_height * 0.8)
x_change = 0
thing_startx = random.randrange,(0, display_width)
thing_starty = -600
thing_speed = 7
thing_width = 100
thing_height = 100
gameExit = False
while not gameExit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x_change = -5
elif event.key == pygame.K_RIGHT:
x_change = 5
if event.type == pygame.KEYUP:
if event.key == pygame.K_LEFT or event.key == pygame.K_RIGHT:
x_change = 0
x += x_change
gameDisplay.fill(white)
things(thing_startx, thing_starty, thing_width, thing_height, red)
thing_starty += thing_speed
car(x,y)
if x > display_width - car_width or x < 0:
crash()
pygame.display.update()
clock.tick(60)
game_loop()
pygame.quit()
quit()
我不知道为什么会这样,我甚至把括号改成了[]
{}
和{
您使用的是
list
类型,应该传递一个tuple
。 这是正确的方法:相反,你有一个var问题:
^{pr2}$你有:
问题是
,
。在相关问题 更多 >
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