在石头、布、剪刀类游戏中使用while循环。（Python）

Question

我尝试使用while循环，这样这个游戏就可以继续玩了，除非用户输入的字符串不是myList中的选项之一。我该把这个while循环放在哪里？（抱歉，我对编码比较陌生）。

import random
def AceDiamondSpade():

    #Set up a list which contains Ace, Diamond and Spade so that the computer can randomly choose one of them.
    myList = ["Ace", "Diamond", "Spade"]
    #
    choice = input("Ace, Diamond, or Spade? ")
    computerChoice = random.choice(myList)
    playAgain = True
    if str(choice) != str(myList[0]) and str(choice) != str(myList[1]) and str(choice) != str(myList[2]):
    playAgain = False 
    print ("invalid! Please enter again or make sure that you have capitalized the first letter of your answer!")
    if str(choice) == str(computerChoice):
        print ("You and the computer selected the same thing, you tie!") 
    if str(choice) == "Ace" and str(computerChoice) == "Diamond":
        print ("You selected Ace, and the comptuer selected Diamond, you win!")
    if str(choice) == "Diamond" and str(computerChoice) == "Spade":
        print ("You selected Diamond, and the Computer selected Spade, you win!")
    if str(choice) == "Spade" and str(computerChoice) == "Ace":
        print ("You selected Spade, and the comptuer selected Ace, you win!")
    if str(choice) == "Ace" and str(computerChoice) == "Spade":
        print ("You selected Ace, and the computer selected Spade, you lose!")
    if str(choice) == "Spade" and str(computerChoice) == "Diamond":
        print ("You selected Spade, and the computer selected Diamond, you lose!")
    if str(choice) == "Diamond" and str(computerChoice) == "Ace":
        print ("You selected Diamond, and the computer selected Ace, you lose!")

Answer 1

import random


def newfunc(string1, string2):
    if string1 == string2:
        print "You selected",string1,"and the computer selected",string2,"you win!"
    else:
        print "You selected",string1,"and the computer selected",string2,"you lose!"

def AceDiamondSpade():
    #Set up a list which contains Ace, Diamond and Spade so that the computer can randomly choose one of them.
    myList = ["Ace", "Diamond", "Spade"]
    #
    while(True):
        choice = raw_input("Ace, Diamond, or Spade? ")
        computerChoice = random.choice(myList)
        if choice not in myList:
            print "That was not a valid choice."
            break
        newfunc(choice,computerChoice)

AceDiamondSpade()

这是基于diegaoguilar的回答，但它增加了一个新功能的前景。在

我敢肯定你只是直接把代码复制/粘贴到网站上，但是要小心缩进，如果可能的话，在行间留出一些间隔，这样会使阅读变得更容易。在

Answer 2

您可以使用类do while，在python中，它是由几个不同的ways组成的：

所以你的代码应该是这样的：

def AceDiamondSpade():

    #Set up a list which contains Ace, Diamond and Spade so that the computer can randomly choose one of them.
    myList = ["Ace", "Diamond", "Spade"]

    while True:
        #Execute your game logic here
        if input("Ace, Diamond, or Spade? ") not in myList:
            break;

在while True你假设下面的代码块（游戏）将无限执行。但是在if条件下，检查结果输入是否不是引用的list的成员，while循环将结束。在

我同意这个评论，你不需要在代码的任何一点使用str。再增加几个函数也会使它看起来更好。在