提供了s3cmd nodename或servname，或未知

Question

我试图用s3cmd和路径样式的url从s3bucket访问对象。这与Java SDK类似没有问题。在

s3Client.setS3ClientOptions(S3ClientOptions.builder()
            .setPathStyleAccess(true).build());

我想用s3cmd做同样的事情。我已经在我的s3conf文件中设置了这个：

^{pr2}$

这适用于存储桶列表：

$ s3cmd ls 
2016-08-24 12:36  s3://test

当试图列出一个bucket的所有对象时，我得到了以下错误：

Traceback (most recent call last):
 File "/usr/local/bin/s3cmd", line 2919, in <module>
rc = main()
 File "/usr/local/bin/s3cmd", line 2841, in main
rc = cmd_func(args)
  File "/usr/local/bin/s3cmd", line 120, in cmd_ls
subcmd_bucket_list(s3, uri)
 File "/usr/local/bin/s3cmd", line 153, in subcmd_bucket_list
response = s3.bucket_list(bucket, prefix = prefix)
 File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 297, in bucket_list
for dirs, objects in self.bucket_list_streaming(bucket, prefix, recursive, uri_params):
 File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 324, in  bucket_list_streaming
response = self.bucket_list_noparse(bucket, prefix, recursive, uri_params)
 File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 343, in bucket_list_noparse
response = self.send_request(request)
 File "/usr/local/lib/python2.7/site-packages/S3/S3.py", line 1081, in send_request
conn = ConnMan.get(self.get_hostname(resource['bucket']))
 File "/usr/local/lib/python2.7/site-packages/S3/ConnMan.py", line 192, in get
conn.c.connect()
 File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 836, in connect
self.timeout, self.source_address)
 File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 557, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
 gaierror: [Errno 8] nodename nor servname provided, or not known

Answer 1

假设您的配置没有其他问题，那么您用于“host_bucket”的值是错误的。在

它应该是：

host_bucket = %(bucket)s.s3.eu-central-1.amazonaws.com

或者

^{pr2}$

第二种方法将使用“路径样式”。但是，如果您使用amazons3和我建议的第一个host_bucket值，s3cmd将根据您在bucket名称中使用的字符自动使用基于dns或基于路径的bucket。在

这是您只想使用基于路径的样式的特殊原因吗？在