我试图用Tkinter制作一个基本的GUI,并使用网格管理器在我的标签旁边有一个输入框,但是如果我在entry对象中使用.Grid(),那么当我运行程序时,窗口就不会显示。在
当我使用.pack()时它确实起作用,这很奇怪,因为我听说在同一个小部件中有其他东西使用.grid()时,我不使用.pack()。我想用网格来组织,因为我想用它。在
代码如下,我在输入对象showName时遇到问题。被注释掉的.pack()语句是有效的,而.grid()语句是不起作用的语句。在
有人知道这是怎么回事吗?在
from Tkinter import *
class RenamerGUI():
def __init__(self, master):
frame = Frame(master)
frame.pack() #Make frame visible
self.exit = Button(frame, text = "Exit", fg = "red", command = frame.quit)
self.csv2tsv = Button(frame, text = "csv2tsv", fg = "green", bg = "black", command=self.csv2tsv)
self.epguidestsvFormatter = Button(frame, text = "epguidestsvFormatter", fg = "green", bg = "black", command = self.epguidestsvFormatter)
self.epNamesList = Button(frame, text = "epNamesList", fg = "green", bg = "black", command = self.epNamesList)
self.SeasonSplitter = Button(frame, text = "SeasonSplitter", fg = "green", bg = "black", command = self.SeasonSplitter)
self.Renamer = Button(frame, text = "Renamer", fg = "green", bg = "black", command = self.Renamer)
self.showLabel = Label(frame, text = "Show: ")
self.showName = Entry(master)
self.get = Button(frame, text = "Get", command = self.textgetter)
self.exit.grid(row=3, column=4)
self.csv2tsv.grid(row=1, column = 0)
self.epguidestsvFormatter.grid(row=1, column=1)
self.epNamesList.grid(row=1, column=2)
self.SeasonSplitter.grid(row=1, column=3)
self.Renamer.grid(row=1, column=4)
self.showLabel.grid(row=2)
self.showName.grid(row=2, column=1)
#self.showName.pack(side=BOTTOM)
条目的父项错误:
应该是
^{pr2}$相关问题 更多 >
编程相关推荐