Python-用于将文本拆分为句子的正则表达式（句子标记化）

Question

我想把一个字符串中的句子列出来，然后打印出来。我不想用NLTK来做这个。因此，它需要在句子末尾的句号上进行拆分，而不是在小数、缩写或名称的标题上，或者如果句子有一个.com，这是在regex上的尝试，但不起作用。

import re

text = """\
Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it. Did he mind? Adam Jones Jr. thinks he didn't. In any case, this isn't true... Well, with a probability of .9 it isn't.
"""
sentences = re.split(r' *[\.\?!][\'"\)\]]* *', text)

for stuff in sentences:
        print(stuff)    

它应该是什么样子的示例输出

Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it. 
Did he mind?
Adam Jones Jr. thinks he didn't.
In any case, this isn't true...
Well, with a probability of .9 it isn't.

Answer 1

尝试根据空格而不是点或?拆分输入，如果这样做，则最终结果中将不会打印点或?。

>>> import re
>>> s = """Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it. Did he mind? Adam Jones Jr. thinks he didn't. In any case, this isn't true... Well, with a probability of .9 it isn't."""
>>> m = re.split(r'(?<=[^A-Z].[.?]) +(?=[A-Z])', s)
>>> for i in m:
...     print i
... 
Mr. Smith bought cheapsite.com for 1.5 million dollars, i.e. he paid a lot for it.
Did he mind?
Adam Jones Jr. thinks he didn't.
In any case, this isn't true...
Well, with a probability of .9 it isn't.