擅长:python、mysql、java
<p>有点混乱,但这是灵活的,这取决于嵌套字典中的属性,并且会将公司放在自己的列中。在</p>
<pre><code>df = pd.DataFrame(columns = ['company'])
i = 0
for company in my_dict:
for nested_dict in my_dict[company]:
df.loc[i,'company'] = company
for attribute in nested_dict.keys():
df.loc[i, attribute] = nested_dict[attribute]
i += 1
</code></pre>
<p>输出:</p>
^{pr2}$