Django:TypeError:“x”是此函数的无效关键字参数

Question

下面的视图可以很好地工作，它利用了“update_or_create”功能，当有东西存在时，它会非常出色地更新记录。但是，如果它不存在并且必须使用create选项来创建一个新记录，我会得到以下错误：

TypeError at /selectteams/1025/3/

'soccerseasonid_id' is an invalid keyword argument for this function

视图如下：

^{pr2}$

以下型号：

class StraightredSeason(models.Model):
    seasonid = models.IntegerField(primary_key = True)
    seasonyear = models.CharField(max_length = 4)
    seasonname = models.CharField(max_length = 36)

    def __unicode__(self):
        return self.seasonid

    class Meta:
        managed = True
        db_table = 'straightred_season'

class UserSelection(models.Model):
    userselectionid = models.AutoField(primary_key=True)
    campaignno = models.CharField(max_length=36,unique=False)
    user = models.ForeignKey(User, related_name='selectionUser')
    teamselection1or2 = models.PositiveSmallIntegerField()
    teamselectionid = models.ForeignKey('straightred.StraightredTeam', db_column='teamselectionid', related_name='teamID')
    fixturematchday = models.IntegerField(null=True)
    soccerseason = models.ForeignKey('straightred.StraightredSeason', db_column='soccerseasonid', related_name='fixture_seasonUserSelection')


    class Meta:
        managed = True
        db_table = 'straightred_userselection'

任何帮助都将不胜感激，非常感谢，艾伦。在

Answer 1

它看起来像是在使用你的默认值，你指定了“soccerseasynid”而不是“soccerseasynd”足球季“你的id”应该有用。在